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If the radius and height of a cone both are increased by 10% then the volume of the cone is increased by what

Posted by Sandeep Bansal 8 years, 9 months ago

CBSE > Class 09 > Mathematics

1 answers

Rashmi Bajpayee 8 years, 9 months ago

Volume of cone = (1/3)πr²h

New Radius = r + 10% of r = 11r/10

New height = h + 10% of h = 11h/10

New Volume = (1/3)(11r/10)²(11h/10)

= (1/3)πr²h × (1331/1000)

Increased volume = (1/3)πr²h - (1/3)πr²h(1331/1000) = (1/3)πr²h(331/1000)

% of increased volume = (New volume/Old volume)×100

= 3.31%

1Thank You

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