A charge 3 coulomb experience a …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Anterpreet Kaur 1 year, 5 months ago
- 0 answers
Posted by Aniket Mahajan 10 months ago
- 0 answers
Posted by Khushbu Otti 1 year, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 4 years, 6 months ago
Force = F = 3000 N (Given)
Charge = q = 3 coulomb (Given)
Distance = d = 10 cm (Given)
According to the formula -
F = qE
F = qV/D
Where, F is the force , q is the charge, V is the potential difference and d is the distance between two points
3000 = 3 × V/10×10-2
V = 1000
Thus, the potential difference between two points separated by a distance of 10 cm along the field line is 1000 Volts.
0Thank You