A charge 3 coulomb experience a …
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Sia ? 4 years, 3 months ago
Force = F = 3000 N (Given)
Charge = q = 3 coulomb (Given)
Distance = d = 10 cm (Given)
According to the formula -
F = qE
F = qV/D
Where, F is the force , q is the charge, V is the potential difference and d is the distance between two points
3000 = 3 × V/10×10-2
V = 1000
Thus, the potential difference between two points separated by a distance of 10 cm along the field line is 1000 Volts.
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