The angle of a quadrilateral are …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Suhas Chinnu 6 years, 4 months ago
- 1 answers
Test
Related Questions
Posted by Kanika . 1 month ago
- 1 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 4 months ago
Let the required angles be (a - 3d)°, (a - d) °, (a + d) ° and (a + 3d) °
Common difference = (a - d) - (a- 3d) = a - d - a + 3d = 2d
We are given that Common difference = 10°
{tex}\therefore{/tex}2d = 10° = d = 5°
We know that sum of four angles of quadrilateral = 360°
{tex}\Rightarrow{/tex} (a-3d)o +(a-d)o+(a+d)o+(a+3d)o=360o
4a=360o
a={tex}\frac{{360}}{4}{/tex}=90o
{tex}\therefore{/tex}a=90o and d=5o
First angle = (a - 3d)° = (90 - 3 × 5) ° = 75°
Second angle = (a - d)° = (90 - 5) ° = 85°
Third angle = (a + d)° = (90 + 5°) = 95°
Fourth angle = (a + 3d)° = (90 + 3 × 5)° = 105°
0Thank You