X×x -2(1+3k)x +7(3+2k)=0 find k
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Gaurie Sharma 6 years, 4 months ago
- 1 answers
Test
Related Questions
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 0 answers
Posted by Parinith Gowda Ms 3 months, 2 weeks ago
- 1 answers
Posted by Sahil Sahil 1 year, 4 months ago
- 2 answers
Posted by Kanika . 1 month ago
- 1 answers
Posted by Vanshika Bhatnagar 1 year, 4 months ago
- 2 answers
Posted by Hari Anand 6 months, 1 week ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 4 months ago
The given equation is
</article>x² - 2x(1 + 3k) +7(3 + 2k) = 0
or x² - 2(1 + 3k)x +7(3 + 2k) = 0
It is given that the given quadratic equation has equal roots,
⇒ b² -4ac = 0
In the given equation we have,
a= 1, b = - 2(1 + 3k) and c= 7(3 + 2k)
Now b² - 4ac = 0
⇒ [ - 2(1 + 3k) ]² - 4 ×1×7(3 + 2k) = 0
⇒ 4×(1 + 3k)² - 4×7(3 + 2k) = 0
⇒ 4(1 + 9k² + 6k) - 4(21 +14k) =0
⇒ (1 + 9k² + 6k) - (21 +14k) = 0
⇒ 1+ 9{tex}k^2{/tex}+ 6k - 21 - 14k = 0
⇒ 9k² - 8k - 20 = 0
Factorize above equation we get
9k² - 18k + 10k - 20 = 0
⇒ 9k( k- 2) + 10(k -2) =0
Therefore, either 9k +10=0 and k -2 = 0
⇒ k= -10/9and k = 2
Hence the values of k are -10/9, 2
0Thank You