Find the HCF of 65 and …

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Sia ? 6 years, 4 months ago
117 = 13 {tex}\times{/tex} 3 {tex}\times{/tex} 3
65 = 13 {tex}\times{/tex} 5
HCF (117, 65) = 13
LCM(117,65) = 13 {tex}\times{/tex} 5 {tex}\times{/tex} 3 {tex}\times{/tex} 3 = 585
Here is given that:
{tex}HCF =65m-117{/tex}
{tex}13=65m-117{/tex}
{tex}65m=130{/tex}
m = {tex}\frac { 130 } { 6 5 } ={/tex}2
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