Three lines 3x+5 y=15,6x -5y=30 and …
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Sia ? 6 years, 4 months ago
{tex}x - y - 5 = 0{/tex}
{tex}\Rightarrow y = x - 5{/tex}
{tex}3x + 5y - 15 = 0{/tex}
{tex}\Rightarrow y = \frac { 15 - 3 x } { 5 }{/tex}
Thus, the two graph lines intersect at {tex}(5, 0){/tex}
{tex}\therefore{/tex} {tex}x = 5\ and\ y = 0{/tex} is the solution of given system of equations
The vertices of the triangle formed by these lines and y - axis are {tex}(5, 0), (0, 3)\ and\ (0, -5){/tex}
So, height of the triangle
= distance from (5, 0) to x-axis
= {tex}5\ units{/tex}
Base = {tex}8\ units{/tex}
Area of the triangle = {tex}\frac { 1 } { 2 } \times \text { base } \times \text{height}{/tex}
{tex}= \frac { 1 } { 2 } \times 8 \times 5{/tex}
= {tex}20\ sq. units{/tex}
0Thank You