if a is a square matrix …

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Sia ? 6 years, 4 months ago
We know that, for a square matrix of order n,
|adj (A) |= |A|n-1
Here, the order of A is 3{tex}\times {/tex}3 ,therefore n = 3
Now, |adj (A) | =|A|{tex}^{3-1}{/tex} = |A|2
Given, |adj (A)|= 64,
Therefore,64 =|A|2
{tex}\Rightarrow{/tex} (8)2 =|A|2
{tex}\Rightarrow{/tex} |A|= ± 8 [taking square root]
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