Find the roots of quadratic equations …

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Sia ? 6 years, 4 months ago
We have, {tex}4x^2 + 4 \sqrt3 x + 3 = 0{/tex}
{tex}\implies (2x)^2 + 2 (2x) (\sqrt3) + (\sqrt3)^2 = 0{/tex}
{tex}\implies (2x + \sqrt3)^2 = 0{/tex}
{tex}\implies 2x + \sqrt3 = 0,\, 2x + \sqrt3 = 0{/tex}
{tex}\implies x = -{\sqrt3 \over 2},\, -{\sqrt3 \over2}{/tex}
{tex}\therefore x = -{\sqrt3 \over 2},\, -{\sqrt3 \over2}{/tex} are the required roots.
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