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tan 13A-tan 9A-tan 4A = tan …

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tan 13A-tan 9A-tan 4A = tan 13A tan 9 A tan 4 A
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Shivani Rana 7 years, 7 months ago

Tan 13 A = tan (9A + 4A) Tan 13A= tan 9A +tan 4A ÷ 1- tan 9A tan 4 A (by using formula tan (A+B)= tan A + tan B ÷ 1 - tan A tan B) By doing cross multiplication Tan 13A (1-tan 9A tan 4A )= tan 9 A + tan4A Tan 13A-tan 13A tan 9A tan 4A = tan 9A +tan 4A Now by shifting Tan 13A -tan 9A -tan 4A=tan 13A tan 9A tan 4A hence proved.....
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