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A narrow 2.5cm in height is …

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A narrow 2.5cm in height is placed at a distance of 25cm from a diverging mirror of focal length 20cm.Find the nature size and image of the object?

Posted by Tanya Jasuja 7 years, 7 months ago

CBSE > Class 10 > Science

1 answers

Yogita Ingle 7 years, 7 months ago

H₁= +2.5cm
u = -25cm
f = +20cm
1/f = 1/v + 1/u
1/20 = 1/v -1/25
1/v = 1/20 + 1/25
1/v = 9/100
v = +11.11 cm
m = h₂/h₁ = -v/u
h₂/2.5 = -11.11/-25
h₂ = +1.11 cm
Hence the image will be formed at 11.11 cm behind the mirror, which will be virtual, erect and of 1.11cm size.

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