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Find the Area of triangle whose two sides are 8cm And 11cm and the perimeter is 32cm.

Posted by Ayush Sandil 8 years, 6 months ago

CBSE > Class 09 > Mathematics

4 answers

Naru Tyagi 8 years, 6 months ago

Sorry half left = _/s(s-a) (s-b) (s-c) = _/16*8*5*3 cm2=8_/30 cm2. *= multiply. 2= square

0Thank You

Naru Tyagi 8 years, 6 months ago

Here we have perimeter of the triangle= 32 cm, a= 8 cm and b= 11 cm. Third side c= 32 cm - (8+11)cm = 13 cm. So, 2s = 32, i.e., s= 16 cm, s- a = (16-8) cm = 8 cm, s-b= (16-11) cm = 5 cm, s-c = (16-13)cm = 3 cm. Therefore, area of the triangle =

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Anshu Madaan 8 years, 6 months ago

13.5

3Thank You

Kashish Singhwaiya 8 years, 6 months ago

a=8 b=11 c=? Perimeter=32 cm a+b+c=32 8+11+c=32 19+c=32 c=13 s=a+b+c/2 s=8+11+13/2 s=16 √s(s-a)(s-b)(s-c) √16(16-8)(16-11)(16-13) √16×8×5×3 √2×8×8×5×3 √2×2×2×2×2×2×2×5×3 2×2×2√2×5×3 8√30

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