If 'm' and 'n' are zeroes …

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Sia ? 6 years, 6 months ago
f(x)=ax2 - 5x + c.
as m and n are zeros of polynomial
therefore m + n = {tex}- \frac { ( - 5 ) } { a } = \frac { 5 } { a }{/tex} and mn = {tex}\frac { c } { a }{/tex}
Now, m + n = 10
{tex}\frac 5a{/tex} =10
so a={tex}\frac12{/tex}
also mn =10 ={tex}\frac { c } { a }{/tex}
10a=c
c=10{tex}\times{/tex} {tex}\frac 12=5{/tex}
hence c = 5 and a ={tex}\frac 12{/tex}
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