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find the value of k if the division of k x cube + 9 X square + 4 x minus 10 by X + 3 leaves remainder -22

Posted by Sahil Kanwal 7 years, 8 months ago

CBSE > Class 09 > Mathematics

1 answers

Armaanjot Singh 7 years, 8 months ago

kx³+9x²+4x-10=0 k(-3)³+9(-3)²+4(-3)-10=0 -3k+27-12-10=0 -3k+27-22=0 -3k+5=0 -3k=-5 k=-5/3

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CBSE > Class 09 > Mathematics