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p(x)=3x²-1,x=-1/√3

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p(x)=3x²-1,x=-1/√3

Posted by Bikash Rajak 7 years, 8 months ago

CBSE > Class 09 > Mathematics

1 answers

Aman Singh 7 years, 8 months ago

As we know that x=1/√3,so by the factor theorem,1/√3 is a factor of p(x) if p(1/√3)=0.now,p(1/√3)=3×(1/√3)wholesquare-1. So,p(x)=1-1. Thus,p(x)=0. Hence,1/√3 is a factor of p(x).

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CBSE > Class 09 > Mathematics