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Pair of linear equations X/2+y=0.8 7/x+y/2=10

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Pair of linear equations X/2+y=0.8 7/x+y/2=10
  • 1 answers

Sia ? 6 years, 6 months ago

Given equations are
{tex}\frac{x}{2} + y = 0.8{/tex}
{tex}\frac{x + 2y}{2} = 0.8{/tex}.
x + 2y = 1.6 ........ (i)
and
{tex}\frac{7}{{x + \frac{y}{2}}} = 10{/tex}
 {tex}\frac{{7 \times 2}}{{2x + y}} = 10{/tex}
{tex}\frac{{7}}{{2x + y}} = 5{/tex}
  7 = 10x + 5y
10x + 5y = 7 .......... (ii)
Multiply first equation by 10
10x + 20y = 16............ (iii)
Subtracting the equations (ii) from (iii) , we get
15y = 9
{tex}y = \frac{9}{{15}} = \frac{3}{5}{/tex}
Put value of y in (i)
{tex}x = 1.6 - 2\left( {\frac{3}{5}} \right) = 1.6 - \frac{6}{5} = \frac{2}{5}{/tex}
Solution is {tex}\left( {\frac{2}{5},\;\frac{3}{5}} \right){/tex}

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