find the value of k for …

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Sia ? 6 years, 6 months ago
We have to find the value of k for which x4 + 10x3 + 25x2 + 15x + k is exactly divisible by x + 7.
If x + 7 is a factor then (-7) is a root.
So f(-7) = (-7)4 + 10 (-7)3 + 25(-7)2 + 15(-7) + k = 0
2401 - 3430 + 1225 -105 + k = 0
or, 3626 - 3535 + k = 0
or, 91 + k = 0
{tex}\therefore{/tex}k = -91
0Thank You