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Find two numbers such that sum …

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Find two numbers such that sum of twice the first and thrice the second is 92 and four times the first exceeds seven times the second by2
  • 1 answers

Sia ? 6 years, 6 months ago

Suppose the first and second number be x and y respectively.
According to the question,
{tex}2x + 3y = 92{/tex} .......(i)
{tex}4x - 7y = 2{/tex} .......(ii)
Multiplying equation (i) by 7 and (ii) by 3, 
{tex}\Rightarrow 14x + 21y = 644{/tex} .......(iii)
{tex}12x - 21y = 6{/tex} .........(iv)
Adding equations (iii) and (iv), 
{tex}\Rightarrow 26x = 650{/tex}
{tex}\Rightarrow x = \frac { 650 } { 26 } = 25{/tex}
Putting {tex}x = 25{/tex} in equation (i), 
{tex}\Rightarrow 2 \times 25 + 3 y = 92{/tex}
{tex}\Rightarrow50 + 3y = 92{/tex}
{tex}\Rightarrow 3 y = 92 - 50{/tex}
{tex}y = \frac { 42 } { 3 } = 14{/tex}
y = 14
{tex}\therefore{/tex} the first number is 25 and second is 14

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