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X^2+9X^2÷(X+3)=27 findX

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X^2+9X^2÷(X+3)=27 findX
  • 1 answers

Rishant Mastwal 7 years, 8 months ago

x^2+9x^2=27(x+3) 10x^2=27x+81 10x^2-27x-81=0 x=-(-27)+_√(27)^2-4(10)(-81)/20 x=27+_√729+3240/20 x=27+_√3969/20 x=27+_63/20 x=90/20=4.5 or x=-46/2=-23
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