A Mason has to fit a …
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Sia ? 6 years, 5 months ago
Given: Size of bathroom = 10 ft by 8 ft.
= (10 {tex}\times{/tex} 12) inch by (8 × 12) inch
= 120 inch by 96 inch
Area of bathroom = 120 inch by 96 inch
To find the largest size of tile required , we find HCF of 120 and 96.
By applying Euclid’s division lemma
120 = 96 {tex}\times{/tex} 1 + 24
96 = 24 {tex}\times{/tex} 4 + 0
Therefore, HCF = 24
Therefore, Largest size of tile required = 24 inches
no.of tiles required {tex} {\text{ = }}\frac{{{\text{area of bathroom}}}}{{{\text{area of 2 tile}}}} = \frac{{120 \times 96}}{{24 \times 24}} = 5 \times 4{/tex} = 20 tiles
Hence number of tiles required is 20 and size of tiles is 24 inches.
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