HCF of 4052 and 12576 equal …

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Sia ? 6 years, 6 months ago
{tex}12576 = 4052 \times 3 + 420{/tex}
{tex}4052 = 420 \times 9 + 272{/tex}
{tex}420 = 272 \times 1 + 148{/tex}
{tex}272 = 148 \times 1 + 124{/tex}
{tex}148 = 124 \times 1 + 24{/tex}
{tex}124 = 24 \times 5 + 4{/tex}
{tex}24 = 4 \times 6 + 0{/tex}
HCF of 12576 and 4052 is '4'.
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