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Solve 4x

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Solve 4x

    • Posted by Manu Kamboj 7 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    The given equation is 4x2 - 4x + 1 = 0

    Here a = 4, b = - 4, c= 1

    {tex}\therefore D=b^2-4ac = (-4)^2-4(4)(1) = 16-16=0{/tex}

    So, the given equation has equal roots

    {tex}x = {-b \pm \sqrt{D} \over 2a} = {-(-4) \pm0 \over 2(4)}{/tex}

    {tex}\implies x={4 \over 8}= {1 \over2}{/tex}

    {tex}Hence,\, x={1 \over 2}, \,{1 \over 2}{/tex}are the required roots.

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