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For which value of k will …

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For which value of k will the following pair of linear equation have no solutions :3x+y=1 (2k-1)x+(k-1)y=2k+1
  • 2 answers

Pawan Shaa 7 years, 8 months ago

In standard form,3x+y_1=0 (2k_1)x+(k_1)y_(2k+1)=0 For no solution a1/a2=d1/d2 and not equal to c1/c2 a1=3 b1=1 c1=-1 a2=2k_1 b2=k_1 c2=2k+1 3/2k_1= 1/ k_1 Solve it , by cross multiplying 3(k_1)=1(2k_1) 3k_3=2k_1 3k_2k=_1+3 K=2 So if we put 3 insite ad of k then there is no solution

Rohit Sharma 7 years, 8 months ago

X=-2 and y=5
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