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A man bought a certain number of toys for rupees 180; he kept one for his own use and sold the others for one rupee each more than he gave for them ,besides his own toy for nothing he made a profit of rupees 10.Find the number of toys.

Posted by Sweta Mishra 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Assume number of toys = x

Therefore, Cost of one toy sold = {tex}\frac{180}{x}{/tex}
Number of toys sold = x - 1
Selling price per toy = Rs.({tex}\frac{180}{x}{/tex} + 1)
Total SP = CP + profit
According to given situation we have,

(x - 1)({tex}\frac{180}{x}{/tex} + 1) = 180 + 10
{tex}\Rightarrow{/tex}(x - 1)({tex}\frac{180}{x}{/tex} + 1) = 190
{tex}\Rightarrow{/tex}x² - 179x - 180 = 190x
{tex}\Rightarrow{/tex}x² - 11x - 180 = 0

After factorising above quadratic equation we get
(x - 20)(x + 9) = 0
{tex}\Rightarrow{/tex}x =20, -9
{tex}\Rightarrow{/tex}x = 20 [ negative value is Rejected i.e., x = -9]

0Thank You

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