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If d the HCF of 45 …

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If d the HCF of 45 and 27 find x y satisfying d= 27x + 45y.

    • Posted by Amit Chandra Jha 6 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    45 = 27 {tex} \times {/tex} 1 + 18
    27 =18 {tex} \times {/tex} 1 + 9
    18 = 9 {tex} \times {/tex} 2 + 0
    So H.C.F. = 9
    Now 9 = 27 – 18 {tex} \times {/tex} 1
    {tex}\style{font-family:Arial}{\begin{array}{l}9=27-18\\=27-(45-27\times1)\times1\\=27-45+27\\=2\times27-(1)\times45=27x+45y\end{array}}{/tex}
    ⇒ x = 2, y = – 1.

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