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For what value of n ,2^n× …

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For what value of n ,2^n× 5^m ends with digits 5
  • 1 answers

Sia ? 6 years, 6 months ago

{tex}\begin{array}{l}(2\times5)^{\mathrm n}=2^{\mathrm n}\times5^{\mathrm n}\end{array}{/tex}

{tex}\text{=10}^n{/tex}

{tex}\text{If n=0 then 10}^0\text{=1}{/tex}

{tex}\text{If n>0 then 10}^n\text{ will end with 0 }{/tex}

{tex}\mathrm{If}\;\mathrm n<0\;\mathrm{then}\;10^{\mathrm n}\;\mathrm{ends}\;\mathrm{with}1\;(\mathrm e.\mathrm g.\;0.1,0.01,0.001){/tex}

Hence  for all values of n,   {tex}2^n\times 5^n{/tex} can never end with 5.

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