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An erect image three times of …

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An erect image three times of an object form at a concave mirror of radius of 36 cm calculate the position of object and image formed at mirror?
  • 1 answers

Piyush Bhatt 7 years, 4 months ago

m=3 R=36 : f=36/2=18 m=-v/u using mirror formula =) =)3=-v/u 1/f=1/v - 1/u =)v=-3u 1/-18=1/-3u - 1/u 3u=-=36 u=-12 v=-3×-12 =36
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