A solid is in the shape …
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Sia ? 6 years, 5 months ago
For Hemisphere,
Radius(r) = 1 cm
{tex}\therefore {/tex} Volume {tex}= \frac { 2 } { 3 } \pi r ^ { 3 }{/tex}
{tex}= \frac { 2 } { 3 } \pi ( 1 ) ^ { 3 }{/tex}
{tex}= \frac { 2 } { 3 } \pi \mathrm { cm } ^ { 3 }{/tex}
For cone,
Radius of the base(r) = 1 cm
Height (h) = 1 cm
{tex}\therefore {/tex} Volume{tex}= \frac { 1 } { 3 } \pi r ^ { 2 } h{/tex}
{tex}= \frac { 1 } { 3 } \pi ( 1 ) ^ { 2 } ( 1 ) = \frac { 1 } { 3 } \pi \operatorname { cm } ^ { 3 }{/tex}
Therefore, volume of the solid
=volume of the hemisphere + volume of cone
{tex}= \frac { 2 } { 3 } \pi + \frac { 1 } { 3 } \pi = \pi \mathrm { cm } ^ { 3 }{/tex}
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