Find derivative of function f(x)=sinx/sinx-cosx with …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Rudra Choudhary 8 years, 9 months ago
- 1 answers
Test
Related Questions
Posted by Ananya Sv 1 year, 4 months ago
- 1 answers
Posted by Sana Dharwad 1 year, 4 months ago
- 0 answers
Posted by Gurleen Kaur 1 year, 4 months ago
- 0 answers
Posted by Nitin Kumar 1 year, 4 months ago
- 1 answers
Posted by Manoj Thakur 1 year, 4 months ago
- 0 answers
Posted by Ashish Chaudhary 1 year, 4 months ago
- 1 answers
Posted by Sethpoulou Apoulou 1 year, 5 months ago
- 0 answers
Posted by Sabin Sultana 1 year, 4 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Naveen Sharma 8 years, 9 months ago
Ans. {tex}f(x) = {sinx\over sinx-cosx}{/tex}
Using quotient Rule, we get
{tex}f'(x) ={ {(sinx-cosx){d(sinx)\over dx}- sinx{d(sinx-cosx)\over dx}}\over (sinx-cosx)^2}{/tex}
{tex}=> { (sinx-cosx)cosx - sinx(cosx-(-sinx)) \over (sinx-cosx)^2}{/tex}
{tex}=> {sinx cosx - cos^2x -sinxcosx -sin^2x\over (sinx-cosx)^2}{/tex}
{tex}=> {- (cos^2x +sin^2x)\over (sinx-cosx)^2}{/tex}
{tex}=> {-1\over (sinx-cosx)^2}{/tex}
0Thank You