Prove that √6+√2 is irrational

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Sia ? 6 years, 5 months ago
Let take that 6 + √2 is a rational number.
So we can write this number as
6 + √2 = a/b
Here a and b are two co-prime number and b is not equal to 0
Subtract 6 both side we get
√2 = a/b – 6
√2 = (a-6b)/b
Here a and b are an integer so (a-6b)/b is a rational number so √2 should be a rational number But √2 is an irrational number so it is contradicting
Hence result is 6 + √2 is a irrational number
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