Can two numbers have 18 as …

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Sia ? 6 years, 6 months ago
We know that HCF of two numbers is a divisor of their LCM. Here, 18 is not a divisor of 380.
But 380 = 18×21+2
Here 2 is remainder so 380 is not divisible by 18.
So, 18 and 380 cannot be respectively HCF and LCM of two numbers.
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