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Calculate the mole fraction of benzoic …

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Calculate the mole fraction of benzoic acid,whose aqueous solution is 40%.

Posted by Ziya Mishra 7 years, 8 months ago

CBSE > Class 12 > Chemistry

1 answers

Tanmaya Nayak 7 years, 8 months ago

As 40% aqueous solution is given, so 40 g of benzoic acid(C6H5COOH) is present in 100g solution. Moles of benzoic acid=(given mass/molar mass) =40/122 =0.32mol Mass of solvent(water)=100-40=60g Moles of water=60/18 =3.33mol Mole fraction of benzoic acid = moles of solute(benzoic acid) / moles of solution (solute +solvent) =0.32/(0.32+3.33) =0.087 Mole fraction of benzoic acid=0.087.

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