Verify that x=3 is a zero …

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Sia ? 6 years, 5 months ago
Here we have function p(x) = 2x3 - 5x2 - 4x + 3
By using remainder theorem, we get
{tex}\therefore{/tex} p(3) = 2(3)3 - 5 {tex}\times{/tex}(3)2 - 4 {tex}\times{/tex}3 + 3
= 54 - 45 - 12 + 3 = 0
{tex}\because{/tex} p(3) =0
Therefore, x = 3 is a zero of p(x).
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