I am three times as old …

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Sia ? 6 years, 6 months ago
Let my age is x years and my son's age is y years.
{tex}\Rightarrow x = 3y{/tex} .............(i)
Five years later, my age will be {tex}(x + 5)years{/tex} and my son's age will be {tex}(y + 5) years{/tex}.
{tex}\therefore{/tex}{tex}x + 5 = \frac { 5 } { 2 } ( y + 5 ){/tex} [Given]
{tex}\Rightarrow{/tex} {tex}2x - 5y -15 =0{/tex} .............(ii)
Putting x =3y in equation (ii), we get
{tex}6y - 5y -15 =0{/tex} {tex}\Rightarrow{/tex} {tex}y =15{/tex}
Putting {tex}y =15{/tex} in equation (i), we get
{tex}x = 45{/tex}
My present age is 45 years and my son's present age is 15 years.
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