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By substituting method 2x - 5y =3 3x - y =11

Posted by Uttam Patidar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Anupam Garg 7 years, 8 months ago

2x-5y=3-1st equation 3x-y=11-2nd equation From 1st equation, 2x-5y=3 2x=3-5y X=(3+5y)/2 Put value of x in 2nd equation 3{(3+5y)/2}-y=11 (9+15y)/2-y=11 9+15y-2y/2=11(here I take the LCM) 9+13y=22(2 multiply with 11 and becomes 22) 13y=22-9 13y=13 Y=13/13 Y=1 Put value of y in 1st equation 2x-5(1)=3 2x-5=3 2x=3+5 2x=8 X=8/2 X=4

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