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Neeraj Sharma 8 years, 9 months ago
{tex}let\,three\,numbers\,b/w\,1\,and\,256\,be\,{G_1},\,{G_2},\,and\,{G_3}{/tex}
{tex}1,{G_1},\,{G_2},\,{G_3},256\,are\,in\,GP{/tex}
{tex}a = 1{/tex}
{tex}l = 256{/tex}
{tex}a{r^4} = 256{/tex}
{tex}{r^4} = 256{/tex}
{tex}r = 4{/tex}
{tex}Now\,{G_1} = ar = 1 \times 4 = 4{/tex}
{tex}{G_2} = a{r^2} = 1 \times {\left( 4 \right)^2} = 16{/tex}
{tex}{G_3} = a{r^3} = 1 \times {\left( 4 \right)^3} = 64{/tex}
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