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4usqare plus 8u , Find the …

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4usqare plus 8u , Find the zeroes and verify the relationship between the zeroes and the cofficients

    • Posted by Bunnu Rawat 7 years, 8 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Piyush Jha 7 years, 8 months ago

    4u²-8u=0 =4u(u-2)=0 =4u=0 =u=0 u-2=0 u= 2 Let us consider 2 as alpha and 0as beta Alpha+beta=-b/a =2+0= 8/4 =2=2 Alpha ×beta = c/a =2×0=0/4 =0=0 Hence relationship has verified

    0Thank You

    Maunisha Mallan Mallan 7 years, 8 months ago

    As it is given.. 4usquare+8u=0 Then.... Take 4 nd u as common,4u(u+2) Equating 4u nd u+2 equal to 0, 4u=0.....u=0 u+2=0....u=-2 Then.....sum of zeroes=-b/a ......0+(-2)=-8/4 -2. = -2 Then.... product of zeroes=c/a ..... ............0*(-2) =0/4 0. = 0

    0Thank You

    Tapan Pandey 7 years, 8 months ago

    Yaar , 4u Ko common Lelo toh (u+2) bachega, fir 4u=0 then u=0, and u+2=0 then u=-2

    1Thank You

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