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The sum of first 4consecutive no. …

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The sum of first 4consecutive no. In a AP is 32 and the ratio of the product of the first and last term to the product of two middle term is 7:15 find the numbers

Posted by Tushar Kumar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Dhananjay Jadhav 7 years, 8 months ago

Let the four consecutive numbers in AP be (a - 3d), (a - d), (a + d) and (a + 3d) So, according to the question. a-3d + a - d + a + d + a + 3d = 32 4a = 32 a = 32/4 a = 8 ......(1) Now, (a - 3d)(a + 3d)/(a - d)(a + d) = 7/15 15(a² - 9d²) = 7(a² - d²) 15a² - 135d² = 7a² - 7d² 15a² - 7a² = 135d² - 7d² 8a² = 128d² Putting the value of a = 8 in above we get. 8(8)² = 128d² 128d² = 512 d² = 512/128 d² = 4 d = 2 So, the four consecutive numbers are 8 - (3*2) 8 - 6 = 2 8 - 2 = 6 8 + 2 = 10 8 + (3*2) 8 + 6 = 14 Four consecutive numbers are 2, 6, 10 and 14

♥️Bhavika Naik?? 7 years, 8 months ago

How did u do that plz explain

Armaan Armaan 7 years, 8 months ago

2,6,10,14

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