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The sum of four consecutive numbers …

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The sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and last term to the product of two middle terms is 7: 15.Find the number

Posted by Neha Soni 7 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Deepanshu Kunal 7 years, 8 months ago

Let four no.'s are:- a-3d,a-d,a+d,a+3d A.T.Q a-3d+a-d+a+d+a+3d=32 4a=32 a=8 Now, (a-3d)(a+3d)/(a-d)(a+d)=7/15 a^2-9d^2/a^2-d^2=7/15 15a^2-135d^2=7a^2-7d^2 8a^2=128d^2 8 (64)=128d^2 512=128d^2 4=d^2 d=+-2 When d=2 No.'s are 2,6,10,14 When d= -2 No.'s are 14,10,6,2

2Thank You

Abhishek Mishradelhi Holy Convent School 7 years, 8 months ago

2,6,10,14

0Thank You

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CBSE > Class 10 > Mathematics