Two different dice are tossed together. …

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Sia ? 6 years, 5 months ago
Total number of possible outcomes = 36
Total number of doublets = 6
{tex}\therefore{/tex} Prob (getting a doublet) = {tex}\frac{6}{36}{/tex}={tex}\frac{1}{6}{/tex}
Number of favorable outcomes =3
{tex}\therefore{/tex} Prob (getting a sum 10) = {tex}\frac{3}{36}{/tex} ={tex}\frac{1}{12}{/tex}
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