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Two different dice are tossed together. Find the probability: 1. Of getting a doublet,2. Of getting a sum of 10 the number less on the two dice

Posted by Deepanshi Goyal 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Total number of possible outcomes = 36

Doublet are { (1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6)}.
Total number of doublets = 6
{tex}\therefore{/tex} Prob (getting a doublet) = {tex}\frac{6}{36}{/tex}={tex}\frac{1}{6}{/tex}
Outcome whose sum of digits is 10 ={(4, 6) (5, 5) (6, 4)}.
Number of favorable outcomes =3
{tex}\therefore{/tex} Prob (getting a sum 10) = {tex}\frac{3}{36}{/tex} ={tex}\frac{1}{12}{/tex}

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