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HCF and LCM of 404 and …

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HCF and LCM of 404 and 96 and verify that HCF ×LCM = product of two no
  • 1 answers

Sia ? 6 years, 6 months ago

Prime factorisation of 404 and 96 is:

404 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 101

404 = 22 {tex}\times{/tex} 101
96 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 3

96 = 25 {tex}\times{/tex} 3
{tex}\therefore{/tex} HCF(404,96 )= 22 = 4
LCM(404, 96 ) = 101 {tex}\times{/tex} 25 {tex}\times{/tex} 3

LCM( 404, 96) = 9696

now we have to verify that,

HCF(404, 96) {tex}\times{/tex}LCM(404, 96) = 404{tex}\times{/tex}96
Hence,

LHS = HCF {tex}\times{/tex} LCM

        = 4 {tex}\times{/tex} 9696

        = 38784
 RHS= Product of numbers

        =404 {tex}\times{/tex} 96 = 38784

Since, LHS=RHS
i.e. HCF {tex}\times{/tex} LCM = Product of 404 and 96.

hence verified

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