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Let cosA+sinA = root2cosA.show that cosA-sinA=root2 …

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Let cosA+sinA = root2cosA.show that cosA-sinA=root2 sinA

Posted by Himanshu Dagar 7 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Chandrashekhar Wankhede 7 years, 8 months ago

Sqr(cos A+sinA)=sqr( /2 *cosA) Sqr(cosA)+2sinAcosA+sqr(sinA)=2*sqr(cosA) 2 sinA cosA = 2*sqr(cosA) -1 Now, sqr(cosA - sinA) = sqr(cosA) - 2sin A cos A + sqr(sinA) .... = 1 - ( 2 Sqr (cos A ) - 1) .... = 2 - 2 Sqr (cos A) .... = 2 ( 1- Sqr (cos A) ) .... = 2 Sqr (sin A) Taking Sqr root on both side, we can prove desired..

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CBSE > Class 10 > Mathematics