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(cosecA -sinA)(secA-cosA)=1/tanA+cotA

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(cosecA -sinA)(secA-cosA)=1/tanA+cotA
  • 1 answers

Megha A 7 years, 8 months ago

LHS: (1/sinA-sinA) (1/cosA-cosA) (1-sin sq A/sinA)(1-cos sq A/cosA) ( cos sq A/sinA)( sin sq A/cosA) = cosAsinA RHS: 1/sinA/cosA+cosA/sinA Sin sq A + cos sq A/sinAcosA 1/1/sinAcosA = sinAcosA LHS =RHS HENCE PROVED
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