If tan=1/3 and tan b=1/2 . …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Tushar Choudhary 8 years, 9 months ago
- 1 answers
Test
Related Questions
Posted by Ashish Chaudhary 1 year, 4 months ago
- 1 answers
Posted by Sethpoulou Apoulou 1 year, 5 months ago
- 0 answers
Posted by Nitin Kumar 1 year, 4 months ago
- 1 answers
Posted by Gurleen Kaur 1 year, 4 months ago
- 0 answers
Posted by Ananya Sv 1 year, 4 months ago
- 1 answers
Posted by Manoj Thakur 1 year, 4 months ago
- 0 answers
Posted by Sabin Sultana 1 year, 4 months ago
- 0 answers
Posted by Sana Dharwad 1 year, 4 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Neeraj Sharma 8 years, 9 months ago
{tex}Given\,that{/tex}
{tex}\tan A = {1 \over 3}\,and\,\tan B = {1 \over 2}{/tex}
{tex}Now\,\,\tan \left( {A + B} \right) = {{\tan A + \tan B} \over {1 - tan A \cdot \tan B}}{/tex}
{tex} = {{\left( {{1 \over 3} + {1 \over 2}} \right)} \over {\left( {1 - {1 \over 3} \cdot {1 \over 2}} \right)}}{/tex}
{tex} = {{\left( {{5 \over 6}} \right)} \over {\left( {{5 \over 6}} \right)}}{/tex}
{tex}\tan \left( {A + B} \right) = 1{/tex}
{tex}A + B = {45^ \circ }{/tex}
{tex}Now\,Sin2\left( {A + B} \right) = \sin \left( {2 \times {{45}^ \circ }} \right){/tex}
{tex} = \sin {90^ \circ }{/tex}
{tex}\sin 2\left( {A + B} \right) = 1{/tex}
0Thank You