The circumference of a circle exceeds …
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Sia ? 6 years, 6 months ago
Let the radius of the circle be r cm.
Its circumference {tex} = 2\pi r\;cm{/tex}
As per the problem,
The circumference of the circle exceeds its diameter by 18 cm
{tex} \Rightarrow {/tex} Circumference – Diameter =180 cm
{tex} \Rightarrow 2\pi r - 2r = 180{/tex}
{tex} \Rightarrow \left( {2 \times \frac{{22}}{7} \times r} \right) - 2r = 180{/tex}
{tex} \Rightarrow \left( {\frac{{44r - 14r}}{7}} \right) = 180{/tex}
{tex} \Rightarrow \frac{{30r}}{7} = 180{/tex}
{tex} \Rightarrow r = \frac{{180 \times 7}}{{30}}{/tex}
{tex}= \frac{{420}}{{10}}{/tex}
= 42 cm
Hence the radius of the circle is 42 cm.
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