Peter throws 2 different dice together …

The person having higher probability of getting the number 25 has the better chance.

When a pair of dice is thrown, there are 36 elementary events  which are as  follows:
 (1, 1) , (1, 2), (1,3), (1,4), (1,5), (1, 6)
(2, 1) , (2, 2), (2,3), (2,4),(2,5), (2, 6)
(3,1) , (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1) , (4,2), (4,3),(4,4), (4,5), (4,6)
(5,1) , (5,2), (5,3), (5,4), (5,5), (5,6)
(6, 1), (6, 2),(6, 3), (6, 4), (6, 5), (6, 6)
Therefore, the product of numbers on two dice can take values 1, 2, 3, ..., 36.
We observe that the  product of two numbers on two dice will be 25 if both the dice show number 5. Therefore,
there is only one elementary event, viz., (5, 5), which is favourable for  getting 25.
p{tex}_1{/tex} = Probability that Peter throws {tex}25 = \frac { 1 } { 36 }{/tex}
Rina throws a die on which she can get any one of the six numbers 1, 2, 3, 4, 5, 6 as an outcome. If she gets number 5 on the upper face of the die thrown,then the square of the number is 25.
p₂ = Probability that the square of number obtained is{tex}25 = \frac { 1 } { 6 }{/tex}
Therefore, p₂ > p₁. Therefore, Rina has better chance to get the number 25.