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tanA + secA - 1/ tanA -secA +1=1+sinA /cosA

Posted by Parv Jain 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Armaan Armaan 7 years, 9 months ago

= tanA+secA-(sec^2A-tan^2)/tanA-secA+1 =tanA+secA-{(secA+tanA)(secA-tanA)/tanA-secA+1 =tanA+secA(1-secA+tanA)/tanA-secA+1 =tanA+secA =sinA/cosA + 1/cosA =1+sinA/cosA??i hope u understand

3Thank You

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