father's age is 3 times the …

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Sia ? 6 years, 6 months ago
Let the present age of father be x years and sum of present age of two son's be y years.
According to question,
after five years
x + 5 = 2(y + 5 + 5)
x + 5 = 2y + 20
x - 2y = 15 ....(i)
and x = 3y ....(ii)
{tex}\therefore{/tex} 3y - 2y = 15
or y = 15
{tex}\therefore{/tex} age of father x = 3y
= 3 × 15
= 45 years
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