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We know that tanx.cosx=sinx and d/dx(sinx)=cosx.differentiate …

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We know that tanx.cosx=sinx and d/dx(sinx)=cosx.differentiate tanx.cosx by prodect rule and cheak that the answer is cosx.
  • 1 answers

Rahul Poddar 8 years, 3 months ago

Yes differentiation of tanx. cosx=cost d (tanx. cosx)/dx=1/cosx-sin^2x/cosx=1-sin^2x/cosx=cos^2x/cosx=cosx
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