Tan a=1÷3, tan b=1÷2 prove that …
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Posted by Gurleen Kaur 8 years, 9 months ago
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Rashmi Bajpayee 8 years, 9 months ago
sin 2(a + b) = 1
2 tan(a + b)/{1 - tan2(a + b)} = 1
2[(tan a + tan b)/(1 - tana.tanb)]/[1 + {(tan a + tan b)/(1 - tana.tanb)}2] = 1
2{(1/3 + 1/2)/1 - 1/3 x 1/2)]/[1 +{(1/3 + 1/2)/(1 - tan a .tan b)}2] = 1
2[(5/6)/(5/6)]/[1 + {(5/6)/(5/6)}2] = 1
2/[1 + 1] = 1
2/2 = 1
1 = 1
Hence proved.
2Thank You